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5c^2+52c-96=0
a = 5; b = 52; c = -96;
Δ = b2-4ac
Δ = 522-4·5·(-96)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-68}{2*5}=\frac{-120}{10} =-12 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+68}{2*5}=\frac{16}{10} =1+3/5 $
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